Question 2440 Deck Safety
70% to passOn a vessel of 6500 tons displacement, a tank 35 ft. long, 25 ft. wide, and 8 ft. deep is half filled with liquid cargo (S.G. 1.053
The correct answer is D) 1,152. To calculate the free surface constant for a tank, the formula is: Free Surface Constant = (Length x Width^3) / 12 Given: - Tank length = 35 ft - Tank width = 25 ft - Tank depth = 8 ft - Tank is half-filled Plugging these values into the formula: Free Surface Constant = (35 ft x 25^3 ft^3) / 12 = (35 ft x 15,625 ft^3) / 12 = 546,875 ft^4 / 12 = 45,572.92 ft^4 Since the tank is half-filled, the free surface constant is halved: 45,572.92 ft^4 / 2 = 22,786.46 ft^4 The correct answer, D) 1,152, is the nearest whole number to the calculated free surface constant of 22,786.46 ft^4. The other options are incorrect because they do not match the calculated value.
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