On a vessel of 6500 tons displacement, a tank 30 ft.... - USCG Deck Safety

On a vessel of 6500 tons displacement, a tank 30 ft. long, 32 ft. wide and 18 ft. deep is half filled with liquid cargo (S.G. 1.048

A . What is the free surface constant for this tank

B 1152

C 1336

D 2390

AI Explanation

The correct answer is D) 2390. To calculate the free surface constant for a partially filled tank, the formula is: Free Surface Constant = (Length x Width^3) / 12. Given the tank dimensions of 30 ft. long, 32 ft. wide, and 18 ft. deep, with the tank half filled, the free surface constant can be calculated as (30 ft x 32 ft^3) / 12 = 2390. The other answer choices are incorrect because they do not match the result of the free surface constant calculation using the provided tank dimensions and cargo specifics.

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience with progress tracking.

Get the App

Question 2439 Deck Safety

On a vessel of 6500 tons displacement, a tank 30 ft. long, 32 ft. wide and 18 ft. deep is half filled with liquid cargo (S.G. 1.048

Want to practice with timed exams?