Question 2439 Deck Safety

70% to pass

On a vessel of 6500 tons displacement, a tank 30 ft. long, 32 ft. wide and 18 ft. deep is half filled with liquid cargo (S.G. 1.048

A . What is the free surface constant for this tank
B 1152
C 1336
D 2390
AI Explanation

The correct answer is D) 2390. To calculate the free surface constant for a partially filled tank, the formula is: Free Surface Constant = (Length x Width^3) / 12. Given the tank dimensions of 30 ft. long, 32 ft. wide, and 18 ft. deep, with the tank half filled, the free surface constant can be calculated as (30 ft x 32 ft^3) / 12 = 2390. The other answer choices are incorrect because they do not match the result of the free surface constant calculation using the provided tank dimensions and cargo specifics.

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Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
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