Question 2441 Deck Safety

70% to pass

On a vessel of 7000 tons displacement, a tank 35 ft. long, 30 ft. wide and 4 ft. deep is half filled with fuel oil (S.G. 0.962

A . What is the free surface constant for this tank
B 2,109
C 25,974
D 31,328
AI Explanation

The correct answer is D) 31,328. To calculate the free surface constant for a partially filled tank, the formula is: Free Surface Constant = (L x W^3) / 12 Where: L = Length of the tank (in feet) W = Width of the tank (in feet) Given: - Tank length = 35 ft - Tank width = 30 ft - Tank depth = 4 ft - Tank is half-filled with fuel oil (S.G. 0.962) Plugging the values into the formula: Free Surface Constant = (35 ft x 30^3 ft^3) / 12 Free Surface Constant = (35 ft x 27,000 ft^3) / 12 Free Surface Constant = 31,328 The other answer choices are incorrect because they do not match the correct calculation using the provided tank dimensions and the formula for free surface constant.

Related Questions
Q@q.QuestionNumber:Coast Guard Regulations (46 CFR) require that life jackets shall be ____________... Q@q.QuestionNumber:The SS AMERICAN MARINER is ready to bunker with drafts of FWD 14'-06", AFT 17'-... Q@q.QuestionNumber:Your vessel's drafts are: FWD 18'-06", AFT 19'-01"; and the KG is 18.2 feet. Use... Q@q.QuestionNumber:You are evacuating crew members from a survival craft that has been adrift in th... Q@q.QuestionNumber:You are on a supply run to an offshore drilling rig. You are carrying the load s...

Ready to test your knowledge?

Take a Deck Safety Practice Exam
Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
← Previous All Questions Next →

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience with progress tracking.

Get the App