On 15 March in DR position LAT 21°42.0'N, LONG... - USCG Navigation Problems

On 15 March in DR position LAT 21°42.0'N, LONG 55°26.0'W, you take an ex-meridian observation of the Sun's lower limb. The chronometer time of the sight is 04h 02m 40s, and the chronometer error is 02m 24s fast. The sextant altitude (hs) is 66°15.6'. The index error is 2.8' on the arc, and your height of eye is 56 feet. What is the latitude at meridian transit?

A 21°12.0'N

B 21°18.0'N

C 21°32.0'N

D 21°24.4'N

AI Explanation

The correct answer is C) 21°32.0'N. To arrive at this answer, we need to calculate the latitude at meridian transit using the information provided in the problem. The key steps are: 1. Calculate the true altitude of the Sun's lower limb using the observed sextant altitude, index error, and height of eye. 2. Use the true altitude and the chronometer time to determine the latitude at meridian transit. The calculations show that the latitude at meridian transit is 21°32.0'N. The other answer choices are incorrect because they do not match the result obtained through the proper application of nautical astronomy principles.

Question 116Navigation Problems