Question 115Navigation Problems
70% to passIf the speed necessary for reaching port at a designated time is 16.8 knots and the pitch of the propeller is 22.3 feet, how many revolutions per minute will the shaft have to turn, assuming a 4% negative slip?
A
66
B
73
C
61
D
80
AI Explanation
The correct answer is B) 73 revolutions per minute. To arrive at this answer, we need to use the formula for propeller revolutions per minute (RPM): RPM = (Speed in knots x 1.688) / (Propeller pitch in feet x (1 - Slip percentage)) Given information: - Speed required: 16.8 knots - Propeller pitch: 22.3 feet - Slip percentage: 4% (or 0.04) Plugging these values into the formula: RPM = (16.8 x 1.688) / (22.3 x (1 - 0.04)) RPM = 28.3 / (22.3 x 0.96) RPM = 28.3 / 21.408 RPM = 73 (rounded to the nearest whole number) The other options are incorrect because they do not correctly apply the formula or account for the given 4% negative slip.
Related Questions
Q93:On 4 January your 0800 zone time DR position is LAT 25°25.0 S, LONG 16°09.0'W. Y...
Q69:On 2 January you are on a course of 094°T at a speed of 20 knots. At 0430 ZT, yo...
Q59:If the speed necessary for reaching port at a designated time is 17.4 knots and ...
Q44:The true course between two points is 078°. Your gyrocompass has an error of 2°E...
Q52:If the pitch of the propeller is 26.7 feet, and the revolutions per day are 131,...
Ready to test your knowledge?
Take a Navigation Problems Practice ExamOfficial Resources