Question 2762 Deck Safety

70% to pass

A cargo of 60 tons is to be loaded on deck 20 feet from the ship's centerline. The vessel's displacement including the 60 ton cargo will be 6,000 tons and the GM two feet. What would be the list of the vessel after loading this cargo?

A 5.4°
B 5.72°
C 6.12°
D 6.4°
AI Explanation

The correct answer is B) 5.72°. To calculate the list of the vessel after loading the 60-ton cargo, we can use the formula for calculating the angle of list: tan(list angle) = (cargo weight x cargo arm) / (displacement x GM). Given: - Cargo weight: 60 tons - Cargo arm: 20 feet - Displacement: 6,000 tons - GM: 2 feet Plugging these values into the formula, we get: tan(list angle) = (60 tons x 20 feet) / (6,000 tons x 2 feet) tan(list angle) = 1,200 / 12,000 tan(list angle) = 0.1 List angle = arctan(0.1) = 5.72° The other options are incorrect because they do not match the calculated value of 5.72°.

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