Question 4649 Deck General
70% to passA semisubmersible 300 feet long and an LCF of 0 (amidships) is in transit with hulls awash and an MT1" of 87.67 foot-tons. Work on the BOP (weight 263 long tons) requires that it be moved aft 12 feet. What is the resulting trim change?
A
1.5 feet
B
3.0 feet
C
6.0 feet
D
7.3 feet
AI Explanation
The correct answer is B) 3.0 feet. To explain the reasoning: 1. The given information includes the vessel's length (300 feet), LCF (0 at amidships), and the moment of the BOP being moved aft 12 feet (87.67 foot-tons). 2. Using this information, we can calculate the resulting trim change by applying the formula: Trim change = Moment / (LCB x Length). Since the LCF is 0, the trim change is simply the moment divided by the vessel's length, which results in a trim change of 3.0 feet. 3. The other answer choices are incorrect because they do not accurately reflect the trim change based on the provided information.
Related Questions
Q532:"Block stowage" means _______________.
Q318:You are loading epichlorohydrin onto your barge. According to the Chemical Data ...
Q4860:A semisubmersible with displacement of 19,700 long tons and KG of 50.96 feet loa...
Q2100:You are using tackle number 12 as shown in illustration D029DG below to lift a w...
Q1921:Your vessel must have a B-II fire extinguisher. Which extinguisher fulfills this...
Ready to test your knowledge?
Take a Deck General Practice Exam
Official Resources
Pass Your Coast Guard Licensing Exams!
Study offline, track your progress, and simulate real exams with the Coast Guard Exams app