Question 70 GLI02 - Mate of Unlimited Tonnage

The Correct Answer is A ### Why Option A ("3,000 lbs.") is Correct The Safe Working Load (SWL) is calculated by dividing the ultimate breaking strain (or ultimate tensile strength) of the material by the required safety factor (SF). The formula is: $$\text{SWL} = \frac{\text{Breaking Strain}}{\text{Safety Factor}}$$ Given values: * Breaking Strain = 15,000 lbs. * Safety Factor (SF) = 5 Calculation: $$\text{SWL} = \frac{15,000 \text{ lbs.}}{5} = 3,000 \text{ lbs.}$$ Therefore, the Safe Working Load is 3,000 lbs. ### Why Other Options Are Incorrect **B) 5,000 lbs.** This result would be obtained if the breaking strain were 25,000 lbs. (25,000 / 5 = 5,000) or if the breaking strain (15,000 lbs.) was divided by 3 (15,000 / 3 = 5,000). It does not use the specified values correctly. **C) 15,000 lbs.** This is the ultimate breaking strain of the line. Using this value as the SWL implies a safety factor of 1, meaning the line is expected to break when the load reaches the limit. A safety factor of 5 requires the SWL to be significantly lower than the breaking strain. **D) 65,000 lbs.** This result would be obtained by incorrectly multiplying the breaking strain (15,000 lbs.) by the safety factor (5) and perhaps adding a slight error (15,000 * 5 = 75,000 lbs.). The SWL must always be lower than the breaking strain, making multiplication the wrong operation.