Question 69 GLI02 - Mate of Unlimited Tonnage
Using a scope of five, determine how many shots of chain you should put out to anchor in 5 fathoms of water?
The Correct Answer is B ### Why option B ("2") is correct Anchoring chain deployment is calculated using the concept of "scope," which is the ratio of the length of the anchor chain deployed to the depth of the water (measured from the water line or the hawsepipe to the bottom). 1. **Calculate Required Chain Length:** * Required Scope (ratio) = 5 * Water Depth = 5 fathoms * Required Chain Length (in fathoms) = Scope $\times$ Depth * $5 \times 5 = 25$ fathoms 2. **Convert Fathoms to Shots:** * Standard maritime measure defines 1 shot of anchor chain as 15 fathoms (90 feet). * Shots required = $\frac{\text{Required Fathoms}}{\text{Fathoms per Shot}} = \frac{25}{15}$ * $25 \div 15 \approx 1.66$ shots. 3. **Determine Practical Deployment:** Since you cannot practically put out 1.66 shots of chain, you must round up to the nearest whole shot to ensure the scope of 5:1 is met or exceeded. Therefore, you must put out **2 shots** of chain (which equals 30 fathoms), resulting in a safe scope of $30/5 = 6:1$. ### Why the other options are incorrect * **A) 1:** One shot is 15 fathoms. Putting out 15 fathoms in 5 fathoms of water gives a scope of $15/5 = 3:1$. This is generally considered inadequate for safely anchoring in anything but the calmest conditions, as the anchor would likely break out under strain. * **C) 3:** Three shots equal 45 fathoms. While safe, this results in a scope of $45/5 = 9:1$. This is significantly more chain than required by the 5:1 specification, leading to wasted time and effort in deployment and retrieval. * **D) 5:** Five shots equal 75 fathoms. This results in an excessively long scope of $75/5 = 15:1$. Deploying this amount of chain is highly inefficient and unnecessary for the stated conditions.
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