Question 857Navigation General

70% to pass

You are underway on course 120°T and your maximum speed is 12 knots. The eye of a hurricane bears 150°T, 120 miles from your position. The hurricane is moving towards 295°T at 20 knots. If you maneuver at 12 knots to avoid the hurricane, what could be the maximum CPA?

A 89 miles
B 96 miles
C 105 miles
D 117 miles
AI Explanation

The correct answer is D) 117 miles. To calculate the maximum closest point of approach (CPA), we need to determine the relative motion between your vessel and the hurricane. Given the information provided, the hurricane is moving at 20 knots towards 295°T, while you are traveling at 12 knots on a course of 120°T. By applying vector analysis, the maximum CPA can be determined as 117 miles. The other options are incorrect because they do not accurately represent the relative motion and the resulting maximum CPA based on the provided parameters.

Related Questions
Q1459:The measurement of local time is based on the passage of the Sun over the ______... Q1095:In a tropical cyclone, in the Northern Hemisphere, a vessel hove to with the win... Q1976:When the moon is new or full, which type of tides occur? Q1345:Steam fog is most likely to occur on the Mississippi and Ohio Rivers in ________... Q435:You wish to measure the distance on a Mercator chart between a point in latitude...

Ready to test your knowledge?

Take a Navigation General Practice Exam
Official Resources
USCG Navigation Rules (COLREGS) 33 CFR Navigation Rules USCG National Maritime Center
← Previous All Questions Next →

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience.

App Store