Question 53Navigation General
70% to passThe Light List indicates that a light has a nominal range of 20 miles and is 52 feet (16 meters) high. If the visibility is 20 miles and your height of eye is 20 feet (6 meters), at what approximate distance will you sight the light?
The correct answer is C) 13.5 nm. To determine the distance at which the light will be sighted, we can use the formula for visual range: visual range (in nm) = 2.076 * sqrt(height of eye (in ft) + 0.8 * height of light (in ft)). Given: - Height of light = 52 ft (16 m) - Height of eye = 20 ft (6 m) - Visibility = 20 miles Plugging these values into the formula: Visual range = 2.076 * sqrt(20 + 0.8 * 52) = 2.076 * sqrt(62) = 13.5 nm The other options are incorrect because: - A (33.0 nm) is too high, as the visibility is limited to 20 miles. - B (20.0 nm) is the nominal range of the light, not the distance at which it will be sighted. - D (8.5 nm) is too low, as the calculated distance is 13.5 nm.
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