Question 79Electricity & Electronics - QMED
70% to passWhat will be the resulting current when a voltage of 442.7 VDC is applied to a resistance of 1.25 ohms in figure "A" of the illustrated circuit when the switch is closed? Illustration EL-0018
A28.25 amps
B35.32 amps
C354.16 amps
D443.62 amps
AI Explanation
The correct answer is C) 354.16 amps. This is calculated using Ohm's law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R). The formula is I = V/R. Plugging in the values given, we get I = 442.7 V / 1.25 ohms = 354.16 amps. The other answer choices are incorrect because they do not properly apply Ohm's law to the given circuit parameters. Choices A, B, and D do not accurately calculate the current when a 442.7 VDC voltage is applied across a 1.25 ohm resistance.
Related Questions
Q185:Attempting to parallel an AC generator which is out of phase with the bus will r... Q417:When a fluorescent lamp has reached the end of its useful life, it should be rep... Q471:When a low input voltage is delivered to a transformer which then produces a hig... Q100:When placed in a magnetic field, which of the materials listed will maintain the... Q430:What should be done when correcting specific gravity readings of a lead-acid bat...
Ready to test your knowledge?
Take a Electricity & Electronics - QMED Practice ExamOfficial Resources