Question 351Electricity & Electronics - QMED
70% to passWhat is the rotor speed of a six pole, 60 cycle, induction motor operating at full load with 3% slip?
A1164 RPM
B1746 RPM
C1800 RPM
D3492 RPM
AI Explanation
The correct answer is A) 1164 RPM. To calculate the rotor speed of a six-pole, 60-cycle induction motor operating at full load with 3% slip, we can use the formula: Rotor speed (RPM) = (120 x f) / (number of poles) x (1 - slip) Where: f = frequency (60 Hz) Number of poles = 6 Slip = 3% (0.03) Plugging in the values: Rotor speed = (120 x 60) / 6 x (1 - 0.03) = 1200 x 0.97 = 1164 RPM The other options are incorrect because: B) 1746 RPM is the synchronous speed, not the rotor speed. C) 1800 RPM is not the correct calculated value. D) 3492 RPM is double the synchronous speed, which is not possible for a six-pole induction motor.
Related Questions
Q196:As shown in figure "1" of the illustration, a correctly connected synchronous tr... Q318:In the illustrated motor controller, what do the contacts across terminals "3" a... Q245:What is the function of the commutator associated with a DC motor? Q114:Besides a condition of overload, what could be a cause of an open armature conne... Q506:When two generators are on the line and are both connected across a shared load,...
Ready to test your knowledge?
Take a Electricity & Electronics - QMED Practice ExamOfficial Resources