Question 159Electricity & Electronics - 1st Asst/Chief
70% to passWhat is the maximum current allowed to be drawn from the secondary of a 2 kVA step-down transformer with a turn’s ratio of four to one if connected across a 440 volt line?
The correct answer is C) 18.1 amps. To calculate the maximum current that can be drawn from the secondary of the 2 kVA step-down transformer, we need to use the formula for power in a transformer: Power (P) = Voltage (V) x Current (I) Given: - Transformer rating: 2 kVA (2000 VA) - Turn's ratio: 4:1 (primary to secondary) - Primary voltage: 440 V To find the secondary voltage, we divide the primary voltage by the turn's ratio: Secondary voltage = 440 V / 4 = 110 V Now, we can use the power formula to calculate the maximum current that can be drawn from the secondary: Power (P) = 2000 VA Voltage (V) = 110 V Current (I) = P / V Current (I) = 2000 VA / 110 V = 18.1 amps Therefore, the maximum current allowed to be drawn from the secondary of the 2 kVA step-down transformer with a turn's ratio of four to one, if connected across a 440-volt line, is 18.1 amps. The other options are incorrect because: A) 1.1 amps is too low for a 2 kVA transformer. B) 4.5 amps is too low for a 2 kVA transformer. D) 22.7 amps is too high for a 2 kVA transformer.
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