Question 113Electricity & Electronics - Assistant Engineer

The correct answer is A) 8.8 ohms. The capacitive reactance (Xc) of a circuit is calculated using the formula Xc = 1 / (2πfC), where f is the frequency of the source and C is the capacitance. In this case, the frequency is 60 Hz, and the capacitances are 100 microfarads (0.0001 farads) for C1 and 200 microfarads (0.0002 farads) for C2. Plugging these values into the formula, we get Xc1 = 1 / (2π * 60 * 0.0001) = 26.5 ohms for C1, and Xc2 = 1 / (2π * 60 * 0.0002) = 13.3 ohms for C2. The total capacitive reactance of the circuit is the parallel combination of these two reactances, which is 8.8 ohms.