Question 2671 Deck Safety

70% to pass

Your vessel displaces 640 tons. The existing deck cargo has center of gravity of 2.3 feet above the deck and weighs 18 tons. If you load 12 tons of ground tackle with an estimated center of gravity of 21 inches above the deck, what is the final height of the CG of the deck cargo?

A 1.75 feet
B 1.94 feet
C 2.08 feet
D 2.26 feet
AI Explanation

The correct answer is C) 2.08 feet. To calculate the final height of the center of gravity (CG) of the deck cargo, we need to use the formula for the weighted average of the CG: (Existing CG x Existing Weight + New CG x New Weight) / (Existing Weight + New Weight) Given: - Existing deck cargo CG: 2.3 feet above the deck - Existing deck cargo weight: 18 tons - New ground tackle weight: 12 tons - New ground tackle CG: 21 inches (1.75 feet) above the deck Plugging in the values: (2.3 feet x 18 tons + 1.75 feet x 12 tons) / (18 tons + 12 tons) = 2.08 feet The other options are incorrect because they do not match the calculated final CG of 2.08 feet above the deck.

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Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
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