Question 2669 Deck Safety

70% to pass

Your vessel displaces 560 tons. The existing deck cargo has a center of gravity of 4.5 feet above the deck and weighs 34 tons. If you load 10 tons of ground tackle with an estimated center of gravity of 2.8 feet above the deck, what is the final height of the CG of the deck cargo?

A 4.11 feet
B 4.36 feet
C 4.57 feet
D 4.78 feet
AI Explanation

The correct answer is A) 4.11 feet. To calculate the final height of the center of gravity (CG) of the deck cargo, we need to use the formula: (Existing CG x Existing Weight + New CG x New Weight) / (Existing Weight + New Weight). The existing deck cargo has a CG of 4.5 feet and weighs 34 tons. The new 10 tons of ground tackle has a CG of 2.8 feet. Plugging these values into the formula, we get: (4.5 x 34 + 2.8 x 10) / (34 + 10) = 4.11 feet. The other options are incorrect because they do not match the calculated result of 4.11 feet.

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Official Resources
46 CFR Lifesaving Equipment USCG Marine Safety Center USCG National Maritime Center
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