Question 2648 Deck Safety
70% to passA vessel displaces 12,000 tons and has a KG of 22.8 feet. What will be the length of the remaining righting arm at an angle of inclination of 60° if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)
The correct answer is D) 1.9 feet. To determine the length of the remaining righting arm, we need to use the formula provided in Section 1 of the Stability Data Reference Book: GZ = GM * sin(theta) - KG * cos(theta) + TG * sin(theta). Given that the vessel displaces 12,000 tons with a KG of 22.8 feet, and the center of gravity shifts 1.8 feet transversely, the calculation yields a righting arm of 1.9 feet at an angle of inclination of 60°. The other options are incorrect because they do not match the result obtained from the formula. Option A (-1.6 feet) and B (-0.1 foot) are negative values, which would indicate a heeling moment instead of a righting moment. Option C (1.2 feet) is not the correct value calculated using the provided information.
Ready to test your knowledge?
Take a Deck Safety Practice ExamWant to practice with timed exams?
Download Coast Guard Exams for the full exam experience with progress tracking.
Get the App