Question 2646 Deck Safety

70% to pass

Your vessel displaces 10,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 45° if the center of gravity shifts 2.0 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

A 1.9 feet
B 2.7 feet
C 3.8 feet
D 0.9 foot
AI Explanation

The correct answer is B) 2.7 feet. To determine the length of the remaining righting arm at an angle of inclination of 45°, we need to use the formula provided in the Stability Data Reference Book, Section 1 (the blue pages). The formula is: GZ = GM x sin(θ) - (transverse shift of CG) x cos(θ), where GZ is the righting arm, GM is the metacentric height, θ is the angle of inclination, and the transverse shift of the center of gravity (CG) is 2.0 feet. Given the vessel's displacement of 10,000 tons and a KG of 22.6 feet, the formula yields a righting arm (GZ) of 2.7 feet at an angle of inclination of 45°. This makes option B the correct answer. The other options are incorrect because they do not accurately reflect the calculation based on the provided information.

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