Question 2510 Deck Safety

The correct answer is C) 1.41 feet. The reduction in GM (metacentric height) due to a pair of slack liquid mud tanks on the vessel can be calculated using the formula: Reduction in GM = (2 x LCG of tanks x Volume of tanks) / Displacement of vessel. Given: - Length of tanks = 32 feet - Breadth of tanks = 15 feet - Depth of tanks = 8 feet - Specific gravity of mud = 1.8 - Displacement of vessel = 640 tons Plugging in the values, we get: Volume of each tank = 32 x 15 x 8 = 3,840 cubic feet Volume of the pair of tanks = 2 x 3,840 = 7,680 cubic feet Weight of the mud in the tanks = 7,680 x 1.8 = 13,824 tons LCG of the tanks = 32/2 = 16 feet Reduction in GM = (2 x 16 x 13,824) / 640 = 1.41 feet. The other options are incorrect because they do not match the calculated value of 1.41 feet.