Question 2507 Deck Safety
70% to passThe liquid mud tanks on your vessel measure 24'L by 16'B by 8'D. The vessel's displacement in fresh water is 864 tons and the specific gravity of the mud is 1.47. What is the reduction in GM due to a pair of these tanks (p/s) being slack?
The correct answer is B) .80 foot. The reduction in GM (metacentric height) due to a pair of slack liquid mud tanks can be calculated using the formula: Reduction in GM = (2 * W * KG) / Displacement, where W is the weight of the liquid in the tanks, KG is the vertical center of gravity of the liquid in the tanks, and Displacement is the vessel's displacement. Given the dimensions of the tanks (24'L x 16'B x 8'D) and the specific gravity of the mud (1.47), the weight of the liquid in the tanks can be calculated as 2 * 24 * 16 * 8 * 1.47 = 5,635.2 tons. Assuming the KG is at the midpoint of the tank depth, the KG is 4 feet. Plugging these values into the formula, the reduction in GM is calculated as (2 * 5,635.2 * 4) / 864 = .80 foot. The other options are incorrect because they do not match the calculated value of .80 foot.
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