Question 2497 Deck Safety

70% to pass

On a vessel displacing 8,000 tons, what is the reduction in metacentric height due to free surface when a tank 45 feet long and 45 feet wide is partly filled with salt water?

A 1.22 feet
B 1.16 feet
C 1.13 feet
D 1.10 feet
AI Explanation

The correct answer is A) 1.22 feet. The reduction in metacentric height due to free surface effect is calculated using the formula: Δ GM = (ρ * b^2 * l) / (12 * Δ), where ρ is the density of the fluid, b is the breadth of the tank, l is the length of the tank, and Δ is the displacement of the vessel. Given the dimensions of the tank (45 feet long and 45 feet wide) and the vessel's displacement (8,000 tons), the calculation results in a reduction of 1.22 feet in the metacentric height, which makes A the correct answer. The other options are incorrect because they do not accurately reflect the reduction in metacentric height based on the provided information.

Ready to test your knowledge?

Take a Deck Safety Practice Exam

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience with progress tracking.

Get the App