Question 2493 Deck Safety
70% to passOn a vessel of 12,000 tons displacement, what is the reduction in metacentric height due to free surface when a tank 60 feet long and 60 feet wide is partially filled with water?
The correct answer is D) 2.57 feet. The reduction in metacentric height due to free surface effect is determined by the formula: GM' = GM - (b^3 * l) / (12 * D), where GM' is the corrected metacentric height, GM is the original metacentric height, b is the breadth of the tank, l is the length of the tank, and D is the displacement of the vessel. Given the vessel's displacement of 12,000 tons and the tank dimensions of 60 feet long and 60 feet wide, the calculation yields a reduction in metacentric height of 2.57 feet, making option D the correct answer. The other options are incorrect as they do not accurately reflect the calculated value.
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