Question 2493 Deck Safety

70% to pass

On a vessel of 12,000 tons displacement, what is the reduction in metacentric height due to free surface when a tank 60 feet long and 60 feet wide is partially filled with water?

A 2.30 feet
B 2.43 feet
C 2.48 feet
D 2.57 feet
AI Explanation

The correct answer is D) 2.57 feet. The reduction in metacentric height due to free surface effect is determined by the formula: GM' = GM - (b^3 * l) / (12 * D), where GM' is the corrected metacentric height, GM is the original metacentric height, b is the breadth of the tank, l is the length of the tank, and D is the displacement of the vessel. Given the vessel's displacement of 12,000 tons and the tank dimensions of 60 feet long and 60 feet wide, the calculation yields a reduction in metacentric height of 2.57 feet, making option D the correct answer. The other options are incorrect as they do not accurately reflect the calculated value.

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