Question 2490 Deck Safety
70% to passA shaft alley divides a vessel's cargo hold into two tanks, each 25 ft. wide by 50 ft. long. Each tank is filled with salt water below the level of the shaft alley. The vessel's displacement is 6,000 tons. What is the reduction in GM due to free surface effect?
The correct answer is C) .62 foot. The reduction in GM (metacentric height) due to the free surface effect can be calculated using the formula: Reduction in GM = IFL / (Volume of Displacement). In this case, the moment of inertia of the free surface (IFL) is calculated as (25 ft)^3 / 12 = 3,125 ft^4 for each tank. With two tanks, the total IFL is 6,250 ft^4. The volume of displacement is 6,000 tons, which is equivalent to 192,000 ft^3. Plugging these values into the formula, the reduction in GM is 6,250 ft^4 / 192,000 ft^3 = 0.62 ft. The other answer choices are incorrect because they do not accurately reflect the reduction in GM based on the given information.
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