Question 2484 Deck Safety
70% to passOn a vessel of 15,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water in the tank tops. The hold is 50 feet long and 60 feet wide. What is the reduction in metacentric height?
A
1.54 feet
B
1.59 feet
C
1.63 feet
D
1.71 feet
AI Explanation
The correct answer is D) 1.71 feet. To calculate the reduction in metacentric height due to free surface in a hold with free water, we can use the formula: Reduction in GM = bl^2 / 12 * Displacement Where: b = width of the hold (60 feet) l = length of the hold (50 feet) Displacement = 15,000 tons Plugging in the values, we get: Reduction in GM = 60 ft * 50^2 ft^2 / 12 * 15,000 tons = 1.71 feet The other answer choices are incorrect because they do not match the result calculated using the formula for free surface effect.
Related Questions
Q7:You are underway in mid-ocean, when you hear a distress message over the VHF rad...
Q2322:Your vessel's drafts are FWD 19'-02", AFT 23'-10". Use the information in Sectio...
Q1429:You are testing the external inflation bladder on an immersion suit and find it ...
Q964:There is an out of control fire on the Auxiliary Machinery Flat. Utilizing illus...
Q1003:In illustration D039SA below, which Fire Control Plan symbol represents a fire s...
Ready to test your knowledge?
Take a Deck Safety Practice ExamOfficial Resources
Pass Your Coast Guard Licensing Exams!
Study offline, track your progress, and simulate real exams with the Coast Guard Exams app