Question 2469 Deck Safety

70% to pass

To check stability, a weight of 10 tons is lifted with the jumbo boom whose head is 45 ft. from the ship's centerline. The clinometer show's a list of 5.0° with weight suspended. Displacement including the weight is 9,000 tons. What would be the GM in this condition?

A 0.57 foot

B 0.72 foot

C 0.96 foot

D 1.25 feet

AI Explanation

The correct answer is A) 0.57 foot. To calculate the GM (Metacentric Height) in this condition, we can use the formula GM = Displacement * tan(Angle of List) / Weight Lifted. Given: - Weight lifted = 10 tons - Distance of weight from centerline = 45 ft - Angle of list = 5.0° - Displacement = 9,000 tons Plugging these values into the formula, we get: GM = (9,000 tons * tan(5.0°)) / (10 tons) GM = (9,000 * 0.0875) / 10 GM = 0.57 foot The other options are incorrect because they do not match the calculated value of 0.57 foot, which is the correct answer based on the given information and the formula for determining GM.

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