You are making a heavy lift with the jumbo boom. Your... - USCG Deck Safety

You are making a heavy lift with the jumbo boom. Your vessel displaces 7940 T. The 45-ton weight is on the pier and its center is 60' to starboard of the centerline. The head of the boom is 110' above the base line and the center of gravity of the lift when stowed on deck will be 50' above the base line. As the jumbo boom takes the strain the ship lists to 4.5°. What is the GM with the cargo stowed?

A 4.82

B 4.64

C 4.30

D 3.97

AI Explanation

The correct answer is B) 4.64. The explanation is as follows: 1. Confirm the correct answer: The correct answer is B) 4.64. 2. Explain the reasoning: To calculate the GM (Metacentric Height) with the cargo stowed, we need to use the formula GM = KB + BM - KG, where KB is the height of the center of buoyancy, BM is the transverse metacentric radius, and KG is the height of the center of gravity. Given the information provided, we can calculate these values and plug them into the formula to determine the GM. 3. Explain why the other options are incorrect: The other options are incorrect because they do not match the correct GM value calculated using the given information. 4. Concise explanation: The correct GM value is 4.64 based on the provided information and the formula GM = KB + BM - KG.

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Question 2465 Deck Safety

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