Question 2462 Deck Safety
70% to passYou are hoisting a heavy lift with the jumbo boom. Your vessel displaces 5230 T. The 35-ton weight is on the pier and its center is 60' to starboard of the centerline. The head of the boom is 105' above the base line and the center of gravity of the lift when stowed on deck will be 42' above the base line. As the jumbo boom takes the strain the ship lists to 5°. What is the GM with the cargo stowed?
The correct answer is C) 4.98. The explanation is as follows: 1. Confirm which answer is correct: The correct answer is C) 4.98. 2. Explain the reasoning or regulation that makes it correct: To calculate the GM (Metacentric Height) with the cargo stowed, we need to consider the moment of the weight, the vessel's displacement, and the list angle. Using the given information, we can calculate the GM using the formula: GM = (Moment / Displacement) / tan(list angle). 3. If relevant, briefly explain why the other options are incorrect: The other options are incorrect because they do not accurately reflect the GM calculation based on the provided information. 4. Keep it concise (2-4 sentences): The correct answer of 4.98 is obtained by correctly applying the GM calculation formula using the given data, resulting in the accurate GM value for the scenario described.
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