Question 2436 Deck Safety

70% to pass

On a vessel of 6500 tons displacement, a tank 30 ft. long, 32 ft. wide and 15 ft. deep is half filled with oil cargo (S.G. 0.948

A . What is the free surface constant for this tank
B 1336
C 2731
D 3240
AI Explanation

The correct answer is D) 3240. The free surface constant for a tank is calculated using the formula: Free Surface Constant = (L x W^3) / 12, where L is the length of the tank, W is the width of the tank, and the tank is assumed to be half-filled. In this case, the tank dimensions are 30 ft long, 32 ft wide, and 15 ft deep. Since the tank is half-filled, the effective depth is 7.5 ft. Plugging these values into the formula, we get: Free Surface Constant = (30 ft x 32^3 ft^3) / 12 = 3240 The other options are incorrect because they do not match the correct calculation. Option A) is not a valid answer, and options B) 1336 and C) 2731 are incorrect numerical values that do not match the proper calculation.

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