Question 2426 Deck Safety

The correct answer is D) 1117 tons. To calculate the displacement of a barge, we can use the formula for the volume of a rectangular prism and then multiply it by the density of salt water, which is approximately 64 lbs/ft³. The barge's dimensions are 85' x 46' x 13', and it's floating with a draft of 10 feet. This means the submerged portion of the barge has a height of 10 feet. Therefore, the volume of the submerged portion is 85' x 46' x 10' = 39,100 ft³. Multiplying this volume by the density of salt water (64 lbs/ft³) gives us a displacement of 2,502,400 lbs, or approximately 1,117 tons, which is the correct answer. The other options are incorrect because they do not accurately reflect the calculated displacement based on the given dimensions and the density of salt water.