Your vessel's draft is 16'-00" fwd. and 18'-00" aft.... - USCG Deck Safety

Your vessel's draft is 16'-00" fwd. and 18'-00" aft. The MT1 is 500 ft-tons. How many tons of water must be shifted from the after peak to the forepeak, a distance of 250 feet, to bring her to an even draft forward and aft?

A 52 tons

B 48 tons

C 24 tons

D 50 tons

AI Explanation

The correct answer is B) 48 tons. To explain: 1) The vessel has a draft of 16' forward and 18' aft, indicating an uneven trim. To bring the vessel to an even draft, the weight must be shifted from the aft to the forward part of the vessel. 2) The formula to calculate the amount of weight that needs to be shifted is: (Aft draft - Fwd draft) x Midship Transverse Moment (MT1) / Distance between FP and AP. Plugging in the values given, we get: (18' - 16') x 500 ft-tons / 250 ft = 48 tons. 3) The other options are incorrect because they do not properly apply the given formula and data.

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience with progress tracking.

Get the App

Question 2315 Deck Safety

Your vessel's draft is 16'-00" fwd. and 18'-00" aft. The MT1 is 500 ft-tons. How many tons of water must be shifted from the after peak to the forepeak, a distance of 250 feet, to bring her to an even draft forward and aft?

Want to practice with timed exams?