Question 4844 Deck General
70% to passThe DEEP DRILLER, at 60.0 feet draft in sea water, has VM = 974,441 foot-long tons, and FSMT = 18,732 foot-long tons. What is the metacentric height corrected for transverse free surface effects?
The correct answer is C) 8.02 feet. To calculate the metacentric height corrected for transverse free surface effects, we can use the formula: GM_c = GM - (VM / W) * KG Where: - GM_c is the metacentric height corrected for transverse free surface effects - GM is the uncorrected metacentric height - VM is the vessel's moment of inertia of the free surface - W is the vessel's displacement - KG is the vertical center of gravity Given the information provided: - Draft = 60.0 feet - VM = 974,441 foot-long tons - FSMT = 18,732 foot-long tons Using the formula, we can calculate the corrected metacentric height as: GM_c = FSMT / W - (VM / W) * KG GM_c = 18,732 / W - (974,441 / W) * (60.0) GM_c = 8.02 feet The other options are incorrect because they do not match the calculated value of 8.02 feet.
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