Question 4817 Deck General

70% to pass

What is the transverse shift in the center of gravity if 200 short tons are placed 10 feet to port of the centerline on a MODU with TCG 0.7 foot starboard of the centerline, and the displacement is 9,000 short tons?

A 0.03 foot
B 0.20 foot
C 0.23 foot
D 0.62 foot
AI Explanation

The correct answer is C) 0.23 foot. To calculate the transverse shift in the center of gravity, we can use the formula: Transverse shift = (Weight x Distance) / Displacement Given: - Weight placed 10 feet to port = 200 short tons - TCG = 0.7 foot starboard of the centerline - Displacement = 9,000 short tons Plugging these values into the formula: Transverse shift = (200 x 10) / 9,000 = 2,000 / 9,000 = 0.23 foot The other options are incorrect because they do not match the result calculated using the formula. Option A (0.03 foot) and Option B (0.20 foot) are too low, while Option D (0.62 foot) is too high.

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