Question 4643 Deck General

70% to pass

The longitudinal free surface correction of a floating MODU displacing 12,000 kips is 1.20 feet. What would be the new FSCL if 2,400 kips of solid variable loads are added?

A 1.50 feet
B 1.20 feet
C 1.00 foot
D 0.83 foot
AI Explanation

The correct answer is C) 1.00 foot. The longitudinal free surface correction (FSCL) is calculated based on the formula FSCL = K * I / V, where K is a constant, I is the moment of inertia of the free surface, and V is the volume of displacement. When the variable loads are increased by 2,400 kips, the volume of displacement will increase, resulting in a decrease in the FSCL value. The formula indicates that as the volume of displacement increases, the FSCL will decrease, leading to the correct answer of 1.00 foot. The other options are incorrect because they do not accurately reflect the change in FSCL due to the increase in variable loads. Option A (1.50 feet) and Option B (1.20 feet) are too high, while Option D (0.83 foot) is too low.

Ready to test your knowledge?

Take a Deck General Practice Exam

Want to practice with timed exams?

Download Coast Guard Exams for the full exam experience with progress tracking.

Get the App