Question 296 Deck General
70% to passThere is a large shipment of case goods available to be loaded on your vessel. You are to load as many tons as possible in a hold which has 32,300 cubic feet left unfilled by cargo. Each case measures 2-feet high by 2-feet wide by 4-feet long and weighs 500 pounds. If you allow a broken stowage allowance of 10% of the 32,300 feet, what is the nearest whole number of tons which may be loaded?
The correct answer is D) 406 tons. To calculate the maximum tonnage that can be loaded, we need to consider the dimensions of the cases and the available cargo space. With a hold size of 32,300 cubic feet and a 10% broken stowage allowance, the effective cargo space is 32,300 * 0.9 = 29,070 cubic feet. Each case measures 2 x 2 x 4 = 16 cubic feet, and weighs 500 pounds. Therefore, the maximum number of cases that can be loaded is 29,070 / 16 = 1,817 cases. At 500 pounds per case, the total weight is 1,817 * 500 = 908,500 pounds, or 406 tons (rounding to the nearest whole number). The other options are incorrect because they do not accurately account for the dimensions and weight of the cases, as well as the broken stowage allowance.
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