Question 22 QMED02 - Electrician-Refrigerating Engineer

The Correct Answer is A. ### Why Option A ("decreases") is Correct This question is directly answered by **Ohm's Law**, which mathematically relates voltage ($V$), current ($I$), and resistance ($R$) as: $$V = I \times R$$ If we rearrange this equation to solve for current, we get: $$I = \frac{V}{R}$$ The problem states that the **voltage ($V$) remains constant**. If the **resistance ($R$) increases**, the current ($I$) must decrease to keep the overall fraction equal to the constant voltage. Current and resistance are inversely proportional when the voltage is held constant. **Conclusion:** If resistance goes up and voltage stays the same, the current must go down (decrease). ### Why Other Options Are Incorrect **B) increases:** This would only happen if the resistance decreased (or if the voltage increased). Since the resistance is increasing, the current must decrease, not increase. **C) increases by the square:** This option incorrectly applies a squared relationship. Current is inversely proportional to resistance, not inversely proportional to the square of resistance. Furthermore, since the current must decrease, any form of "increase" is incorrect. **D) remains the same:** Current only remains the same if both the voltage and resistance are unchanged, or if both increase or decrease proportionally. Since the voltage is constant and the resistance is increasing, the current must change (decrease) according to Ohm's Law.