Question 55 GLI04 - Mate of LT 500-1600 GRT

The Correct Answer is C ### Explanation for Option C (Correct Answer) The requirement for carbon dioxide (CO2) fixed fire extinguishing systems in a cargo space on a freight vessel is governed by maritime safety regulations (e.g., SOLAS, USCG regulations). The standard requirement is 1 lb of CO2 for every 30 cubic feet of gross volume of the protected space. **1. Calculate the volume of the cargo space:** $$Volume = Length \times Width \times Height$$ $$Volume = 45 \text{ ft} \times 36 \text{ ft} \times 62 \text{ ft}$$ $$Volume = 100,440 \text{ cubic feet} (\text{ft}^3)$$ **2. Calculate the required mass of CO2:** The standard ratio is 1 lb of CO2 per 30 ft$^3$. $$Required \text{ CO2} (\text{lbs}) = \frac{Volume (\text{ft}^3)}{30 \text{ ft}^3/\text{lb}}$$ $$Required \text{ CO2} (\text{lbs}) = \frac{100,440}{30}$$ $$Required \text{ CO2} (\text{lbs}) = 3,348 \text{ lbs}$$ Therefore, 3,348 pounds of carbon dioxide are required for this cargo space. --- ### Why Other Options Are Incorrect **A) 1674:** This value is exactly half of the required amount (3348 / 2 = 1674). This might result from calculating the volume and then dividing by 60 instead of 30, or by miscalculating the volume. It does not meet the regulatory requirement of 1 lb per 30 ft$^3$. **B) 2511:** This option corresponds to a ratio of 1 lb per 40 ft$^3$ (100,440 / 40 = 2511). While some specific spaces (like machinery spaces) might have different application rates, the standard for a general cargo space is 1 lb per 30 ft$^3$. This amount is insufficient for the protected volume. **D) 5022:** This option corresponds to a ratio of 1 lb per 20 ft$^3$ (100,440 / 20 = 5022). While providing more CO2 than required is generally safer, the question asks for the required amount based on standard regulations. This excessive amount would not be the minimum requirement for certification.